Plis pa answer :D kikis ko luh lang What are the roles of a little bulb according to poem?
1. Plis pa answer :D kikis ko luh lang What are the roles of a little bulb according to poem?
Answer:
fr ee code para sa mga nag ro r o b l o x diyan
at fr ee bobux enter yo po iyan mag kakaroon kayo ng 1000k robux
CODE: Slither,Youtube.178902. Use the calculator to check your answer and explain your Examples Why? log, 3=1 log.m=? log, 11=1 log, I = 0 log. 1 = ? log, I = 0 549,1 =10 29.5 = 5 log, 12 = 2.26 log, (4(3) = log: 4 + log: 3 = 2.26 logy? 16 log. 2 log, 16-log, 2-3 log Y - ? log, 2-4log, 2 log, 72 - 2log,7 log, m=?
Answer:
Use the calculator to check your answer and explain your Examples Why? log, 3=1 log.m=? log, 11=1 log, I = 0 log. 1 = ? log, I = 0 549,1 =10 29.5 = 5 log, 12 = 2.26 log, (4(3) = log: 4 + log: 3 = 2.26 logy? 16 log. 2 log, 16-log, 2-3 log Y - ? log, 2-4log, 2 log, 72 - 2log,7 log, m=?
3. Write log w + log x – log y – log z as a single logarithm. A. log wx/yz B. log xy/wz C. log yz/wx D. log wz/xy
Answer:
A
Step-by-step explanation:
4. 1. log, 25=3x-32. log.(x+3)=3/23. logu2(3-X)=-34. log, 2x-log(x+5)=05. log, (log, 256)=36. log; (3x-2)<27. log;(x-1)? > 28. log; x+log6229. log, x-3 log, 25110. log, x+log2 (x+4)<5
Answer:
45
Step-by-step explanation:
tree or four beacuse of 10
5. condense each expression to a single logarithm,1. log 3 - log 82. log u + log v 3. log 5 + log 6, help need ngayon :((
Step-by-step explanation:
1. log 3 - log 8
= log (3/8)
2. log u + log v
= log (uv)
3. log 5 + log 6
= log (5*6)
= log 30
6. (log³2)(log³4)=log³6trueFalse
Answer:
tjhc ohvohvojbjbkbknkmb
7. 1. Write each sum or difference as a single logarithm. (50 points) of a) 1. Log33+ log: 4 2. Log (3x + 4) - log x 3. 2 log x + log (x + 2) 4. Log x + 3 log (x-3) 3 n) 5. 5 log (x + 3) - log x -
Step-by-step explanation:
Answer:
1. x= 5/3
2. x= 5
3. x= -5
4. x= 5
5. x= ³√log²250
Step-by-step explanation:
1) Rearrange unknown terms to the left side of the equation: -3x=-3 in log⁵25
Reduce the greatest common factor on both sides of the equation: 3x= 3 + log⁵25
Divide both sides of the equation by the coefficient of variable: x= (3+log⁵25)÷3
Factorize the argument: x= (3+log⁵5²)÷3
Apply power law of logarithm to simplify the expression: x=(3+2)÷3
Calculate the sum or difference: x=5÷3
Rewrite as fraction: x=5/3
8. solve log y=log 5,934+0.885 log ×
Answer:
calculator mo nlng mas mabilis pa
9. log(4+x)-log(x-3)=log
Answer:
2log mo yan
Step-by-step explanation:
1. magsipilyo
2.humiga
3. pumikit
4. kumopya
10. valuation:1.) A pile of logs has 2 logs in the top layer, 3 logs on the second layer, 4 logs on the third layer,and so on. If there are 30 layers of log, how many logs are there in all?
Answer:
252 is thw right answer
Answer:
490
Step-by-step explanation:
2 + 3 +4 + 5 +6 +7 + 8 + 9 +10 + 11 + 12 + 13 + 14 +15 + 16 +17 + 18 + 19 +20 +21 + 22 + 23 +24 + 25 + 26 + 27 + 28 + 29 + 30 + 31 = 490
11. Use the calculator to check your answer and explain your Examples Why? log, 3=1 log.m=? log, 11=1 log, I = 0 log. 1 = ? log, I = 0 549,1 =10 29.5 = 5 log, 12 = 2.26 log, (4(3) = log: 4 + log: 3 = 2.26 logy? 16 log. 2 log, 16-log, 2-3 log Y - ? log, 2-4log, 2 log, 72 - 2log,7 log, m=? Pasagot nga po plss
Answer:
Step-by-step solved example in Log:
1. Find the logarithms of:
(i) 1728 to the base 2√3
Solution:
Let x denote the required logarithm.
Therefore, log2√3 1728 = x
or, (2√3)x = 1728 = 26 ∙ 33 = 26 ∙ (√3)6
or, (2√3)x = (2√3)6
Therefore, x = 6.
Solution:
Let y be the required logarithm.
Therefore, log0.01 0.000001 = y
or, (0.01y = 0.000001 = (0.01)3
Therefore, y = 3.
Step-by-step explanation:
㋛︎I hope its help✔︎
JAY❤︎シ︎12. I can’t solve this… Write as one logarithm and simplify as possible: (log 3 - log 6) + log 2 Choices: Log 1 Log 6 Log 2 Log 4
To combine logarithms with the same base, we can add or subtract the coefficients. In this case, the base for each logarithm is the same, so we can subtract the coefficients of the logarithms in the parentheses to get:
$$\log 3 - \log 6 + \log 2 = \log 3 - 1 + \log 2$$
We can then simplify this expression further by using the property of logarithms that states that $\log a^b = b \cdot \log a$. This allows us to rewrite $\log 3$ as $\log 2^{\log 3}$, and $\log 2$ as $\log 2^1$. Substituting these expressions into the above equation, we get:
$$\log 2^{\log 3} - 1 + \log 2^1 = \log 2^{\log 3 - 1 + 1} = \log 2^{\log 3} = \boxed{\text{Log 4}}$$
Note that the expression in the parentheses is equivalent to $\log 3 - \log 6 = \log \frac{3}{6} = \log \frac{1}{2} = -\log 2$, so the final result is equivalent to $\log 2^{-\log 2} = \log 2^{-1} = \log \frac{1}{2} = -\log 2$. However, since the question asks us to write the answer as a logarithm, we use the property of logarithms mentioned above to write the answer in logarithmic form.
13. 1. log₂ 9x + log₂ 9 = log₂ 72
Answer:
di ako sure kung tama yan
14. log(a-b)= log a-b log b true or false
Answer:
sinsha sakit din ulo ko ngayon
15. log 6 - log x= log (6x-5) answer
Answer:
x = (-2/3, 3/2)
Step-by-step explanation:
[tex]log \: 6 \: - log \: x \: = log \: (6x - 5) \\ log \: (\frac{6}{x}) = log \: (6x - 5) \\ \frac{6}{x} = 6x - 5 \\ 6 {x}^{2} - 5x - 6 = 0 \\ (3x + 2)(2x - 3) = 0 \\ x = - \frac{2}{3} \\ x = \frac{3}{2} [/tex]
16. (log³ 2) (log³ 4) = log³ 6
Checking the equality:
(log^3 2)(log^3 4) = log^3 6
0.796145=1.63093
Solution: False
17. Which is the simplified form of log 6 + log x? Select one: a. log 6x b. log 6/x c. log 6x d. log x/6
Answer:
a. log 6x
Step-by-step explanation:
log 6 + log x = log 6x
18. A pile of logs has 24 logs in the first 23 logs in the second layer 22 logs in the third layer and so on.how many logs are there in 10 layers.
14 logs on the 10th layer
19. simplify log 6 + log 3 - log 9
Answer:
LOG-LOGIC MOMMY AND MAMA YOUR MAMA ANSWER YOUR QUESTIONS
20. If log 2 = 0.301 and log 3 = 0.477, find log 24
The value of log(24) is 1.38
ㅤ
Given the values of log(2) and log(3):
[tex]\begin{cases} \log 2=0.301 \\ \log 3=0.477\end{cases}[/tex]
Since these values are given, we can probably use the values to find the value of log 24. Observe that 24 is equal to 2³ x 3, hence:
[tex]\log(24)=\log(2^3 \times 3)[/tex]
The expression inside the logarithm is the product of 2³ and 3, so using the product rule of logarithm, we get that:
[tex]\log(24)=\log(2^3)+\log(3)[/tex]
We can write log(2³) as 3log(2) by using the power rule. Therefore,
[tex]\log(24)=3\log(2)+\log(3)[/tex]
Now, substitute the given values of log 2 and log 3.
[tex]\log (24) = 3(0.301)+0.477[/tex]
[tex]\log (24)=0.903+0.477[/tex]
[tex]\log(24)=1.38[/tex]
Thus, the value of log(24) is 1.38.
ㅤ
Hope it helps.
21. log(2 \times + 5) > log(3x - 1)log(2×+5)>log(3x−1)
sorry i need points ;( sorry sorry sorry
22. Investigate! Study the table below and provide the information needed to complete the table. Use the calculator to check your answer and explain your answer. Examples Why? log... m=? log, 31 log, 11=1 log, I = 0 1 log, 1=0 log. 1 = ? 5kg, 10 lo? 10 2825 = 5 log, 12 = 2.26 log (4)(3) = log, 4+log, 3 = 2.26 log... ty = ? log2 16 2. = log, 16-log, 2 = 3 log. ? y log, 2' = 4 log, 2 log, 7' = 2 log, 7 log, m' = ?
Answer:
[tex]54.3919 \\ 26x269..38y6955555 { < .}^{?} \times \frac{?}{?} [/tex]
23. (log₅5)(log10)(log₁₅15)(log₂₀20)
(log₅5)(log10)(log₁₅15)(log₂₀20) = (1)(1)(1)(1) = 1
24. log(x²-2) + 2 log 6 = log 6x
Solving Logarithmic EquationsSolution:
[tex]log(x^2-2) +2log(6) = log(6x) \\ log(x^2-2) +log(6^2) = log(6x) \\ log(x^2-2) +log(36) = log(6x) \\log(x^2-2) = log(6x) -log(36) \\ log(x^2-2) = log(\frac{6x}{36}) \\ log(x^2-2) = log(\frac{x}{6}) \\x^2 -2 = \frac{1}{6}x \\ x^2 -\frac{1}{6}x -2 = 0 \\ x^2 -\frac{1}{6}x = 2 \\ x^2 -\frac{1}{6}x +\frac{1}{144} = 2 +\frac{1}{144} \\ (x -\frac{1}{12})^2 = \frac{288 +1}{144} \\ (x -\frac{1}{12})^2 = \frac{289}{144} \\ \sqrt{(x -\frac{1}{12})^2} = ±\sqrt{\frac{289}{144}} \\ x -\frac{1}{12} = ±\frac{17}{12} \\ x = ±\frac{17}{12} +\frac{1}{12}[/tex]
Solving for [tex]x[/tex] from the equation that has the positive square root:
[tex]x = \frac{17}{12} +\frac{1}{12} \\ x = \frac{17 +1}{12} \\ x = \frac{18}{12} \\ x = \frac{3}{2}[/tex]
Solving for [tex]x[/tex] from the equation that has the negative square root:
[tex]x = -\frac{17}{12} +\frac{1}{12} \\ x = \frac{-17 +1}{12} \\ x = \frac{-16}{12} \\ x = -\frac{4}{3} [/tex]
Answer:[tex]x = \frac{3}{2}\\[/tex] and [tex]x = -\frac{4}{3}\\[/tex] satisfy your logarithmic equation.
25. given log 2 =0.3010,log 3 =0.4771,log 5 =0.6990.evalute log 120
Thanks!Pa Brainliest :) Salamat!
26. Activity 2.3. Find the value/s of x in the following equations/inequalities 1. log, 25 = 3x - 3 2. log. (x+3) = 3/2 3. log12(3- x)=-3 4. log; 2x - log: (x+5)=0 5. log, (log, 256) = 3 6. log; (3x - 2) 2 8. log; x+log, 622 9. log; x – 3 log; 251 х 10. log x + log2 (x+4)
Answer:
1.x=5/3
2.x=5
3.x=-5
4.x=5
5.x=³√log²250
Step-by-step explanation:
pa brainliest po
27. log 7 [x⁴/ y²]log 7 [ 2³/5²]log 3 (z³÷xy)log t [ a³/b³]log 6 (uv³)²
Answer:
190(580log585)190
Step-by-step explanation:
thats the correct answer
28. Express the following as single logarithms. 1. log 5 log 4 2. log 7 - log 14 3. 2 log 3 3 log 2 4. 2 log 9 - 3 log 3
Answer:
5736344444567743864965
29. log (x + 8) = log x + log 8 ² ² ²
Answer:
log(x+8)=log(x)+log(8222)
log(x+8)=log(x)+200.485977
Step-by-step explanation:
30. log 7 [x⁴/ y²]log 7 [ 2³/5²]log 3 (z³÷xy)log t [ a³/b³]log 6 (uv³)²
Answer:
***luv(*+333+)*luv***
