The following data are for a falling- head permeability test:
1. The following data are for a falling- head permeability test:
Answer:
wala picture po hindi ko makita
2. The permeability of a semi-impervious soil was determined in a falling head permeameter whose head decreased from 100 cm to 40cm in n 5 minutes
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3. What is the permeability of cellb membrane? A. diffirentially permeable. B. fully permeable. C. Not permeable. D. directly permeable.
Answer:
A.diffirentially permeable
4. it is a discipline of gymnastic in which athletics perform short run test on different apparatus
Answer:
Artistic gymnastics is a discipline of gymnastics in which athletes perform short routines on different apparatuses.
Explanation:
hp it hewlps u
5. 1. Which set-up has higher rate of permeability? 2. Which set-up has the lower rate of permeability? 3. How do you describe the permeability rate of clay?
Answer:
huy ag module kan
btw classmate ka
Explanation:
thank you newtons
6. how will you differentiate bp apparatus digital, bp apparatus aneroid and bp apparatus mercurial?
Answer:
A sphygmomanometer is a medical device for measuring blood pressure. It employs a cuff that attaches around the arm of the patient. Two main types include mercury, referring to the liquid element used for measurement, and aneroid sphygmomanometer, indicating the lack of any liquid.
7. is cell membrane a permeable membranetrue or falseif false what is a permeable membrane
Answer:
False
Explanation:
It is a membrane that permits passage of water and certain substances in solution. It is something that is permeable can be passed through, especially by liquids or gases. A permeable surface allows materials like liquids to pass through — either in or out. Inside the body, the walls of cells are permeable membranes that allow fluids and nutrients to get in and nourish the cells.
8. Do you think equilibrium apparatus of the inner ear was operating equally well in all these tests
Answer:
Yes
Explanation:
What conclusions can you draw regarding the factors necessary for maintaining balance? Maintaining body equilibrium and balance requires sensory input from three sources: the vestibular apparatus (vestibule and semicircular canals), the proprioceptors, and the eyes.
9. These are factors that are tested in the experiments.a. Variablesb. Materialsc. Specimendonda Variabled. Apparatus
D appraratus im not sure
10. 7.A membrane that allows all materials to pass through isa. selectively permeable.b. impermeableC. permeabled. none of these
the answer is c. permeable
11. example of water permeable
Answer:
brailiest Muna Bago answer
Answer:
A cloth that liquids can pass right through is an example of something that would be described as permeable. Of or relating to substance, substrate, membrane or material that absorbs or allows the passage of fluids.
Explanation:
Rainwater sinks through permeable rock to form an underground reservoir.
12. is dermis permeable?
Answer:
Permeability. Human skin has a low permeability; that is, most foreign substances are unable to penetrate and diffuse through the skin. Skin's outermost layer, the stratum corneum, is an effective barrier to most inorganic nanosized particles.
13. The relative permeability of a material is 60. what is the permeability of the material
SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & \mu_{\text{r}} = 60 \\ & \mu_{0} = 4\pi \times 10^{-7} \: \text{H/m} \end{aligned}[/tex]
Step 2: Calculate the permeability.
[tex]\begin{aligned} \mu & = \mu_{\text{r}} \mu_{0} \\ & = (60)(4\pi \times 10^{-7} \: \text{H/m}) \\ & = \boxed{7.54 \times 10^{-5} \: \text{H/m}} \end{aligned}[/tex]
Hence, the permeability of the material is 7.54 × 10⁻⁵ H/m.
[tex]\\[/tex]
#CarryOnLearning
14. what is air permeability
Air Permeability is defined as the rate of airflow passing perpendicularly through a known area under a prescribed air pressure differential between the two surfaces of a material.
15. Do you think equlibrium apparatus of theh inner ear was operating equally well in all these tests
Answer:
requires sensory input from three sources: the vestibular apparatus (vestibule and semicircular canals), the proprioceptors, and the eyes.
16. experience to test a hypothesis i will use a conduct lee apparatus the detailed steps will be as follows
Answer:
Statistics is all about data. Data alone is not interesting. It is the interpretation of the data that we are interested in. Using Hypothesis Testing, we try to interpret or draw conclusions about the population using sample data. A Hypothesis Test evaluates two mutually exclusive statements about a population to determine which statement is best supported by the sample data. Whenever we want to make claims about the distribution of data or whether one set of results are different from another set of results in applied machine learning, we must rely on statistical hypothesis tests.
Explanation:
17. Activity 3:Permeability
Answer:
first do what it said then second observe it
Explanation:
ihope that helps
18. Permeable means?help
Answer:
b.
Explanation:
nothing can pass through it
19. which of the following describes a cell membrane??a. permeableb. impermeable c semi permeabled. non of these
Answer:
C.
Cell membrane is the semipermeable membrane surrounding the cytoplasm of a cell.
20. A test is set up as shown. A cylindrical mold 4" in diameter is filled with silt to height of H1=0.2ft whose coefficient of permeability is 3.6x10^-4 ft/min. A second coaxial mold is placed on the top of the first mold whose inside legs of the square tube is 1.5" and whose height is H2=0.3ft. Its thickness is negligible. The inside of the second mold is filled with sand whose coefficient of permeability is 2.7x10^-3 ft/min but the outside of the second mold is filled with the same silt. The test set up is constant head. Water is placed on molds and maintained at the level 1.25ft above the level of outlet. It may be consider that the system consist of fictitious soil of thickness H1 H2 and the coefficient of permeability of both soils is Kf, determine the Kf in ft/min.
SOIL MECHANICS
The study of soil, its behavior, and its use as a material for engineering is the focus of the civil engineering subject known as soil mechanics.
Given:
You can apply the formula for the permeability coefficient of a composite material to figure out the permeability coefficient (Kf) of the made-up soil in the system:
Kf is equal to (A1 + A2) / (K1 + K2 A1)Where K1 and K2 are the permeability coefficients for the sand and silt, respectively, and A1 and A2, respectively, are the cross-sectional areas of the two materials.Solution:
The formula for the area of a cylinder can be used to determine the cross-sectional area of the silt:
A1 = πr^2
= π(4/2)^2
= 16π
You can apply the formula for calculating a square's area to determine the sand's cross-sectional area:
A2 = s^2
= (1.5/2)^2
= 0.5625
The following results are obtained by entering these values into the composite coefficient of permeability formula:
Kf = (3.6e-4 * 16π + 2.7e-3 * 0.5625) / (16π + 0.5625)
= 4.68e-4 feet/minute
This is the system's imaginary soil's permeability coefficient.
Mechanical manipulation of soil:
https://brainly.ph/question/6570200
#SPJ4
21. 3. This is a property of cell membranes:a. solubleb. permeabled. semi-permeablec. non-permeable
a. soluble
because the property of cell membrane called soluble
22. experiment to test my hypothesis, i will use a conductivity apparatus. the detailed will be as follows. first____second ___third__then____and finally
Answer:
lekdokdoddoffkkfkffd
Explanation:
fffffdddmdkdmdmdkkdkd
23. For a constant laboratory perneability test on a fine sand, the following data are given: determine the coefficient of permeability in cm/sec and seepage velocity in cm/sec
Answer:
saan Ang sasagutan
Explanation:
where
24. calculate the coefficient of permeability of a soil sample, 8 cm in height and 55 cm2 in cross-sectional area, if a quantity of water equal to 600 ml passed down in 15 minutes under an effective constant head of 60 cm. On over drying the test specimen weighs 650 gms. Taking the specific gravity of solids as 2.67 ,calculate the Seepage velocity of water during the test.
Answer:
[tex]k=1.6162\times10^{-3}[/tex] cm/sec
[tex]v_s=0.0259[/tex] cm/sec
Explanation:
FORMULAS:
Constant head permeability test:
[tex]k=\dfrac{VL}{Aht}[/tex]
where:
k = coefficient of permeability
V = volume of water collected
L = length of the soil specimen
A = cross-sectional area of the soil specimen
h = constant head
t = duration of water collection
Discharge velocity:
[tex]v=ki[/tex]
where:
v = discharge velocity
k = coefficient of permeability
i = hydraulic gradient (i = h/L)
Seepage velocity:
[tex]v_s=\dfrac{v}{n}[/tex]
where:
[tex]v_s[/tex] = seepage velocity
v = discharge velocity
n = porosity
Dry unit weight:
[tex]\gamma_d=\dfrac{Ws}{V}[/tex]
[tex]\gamma_d=\dfrac{G_s\gamma_w}{1+e}[/tex]
where:
[tex]\gamma_d[/tex] = dry unit weight
[tex]W_s[/tex] = weight of the soil solids
V = volume of the soil specimen
[tex]G_s[/tex] = specific gravity of the soil solids
[tex]\gamma_w[/tex] = unit weight of water
e = void ratio
Porosity:
[tex]n=\dfrac{e}{1+e}[/tex]
where:
n = porosity
e = void ratio
SOLUTION:
1. Coefficient of permeability, k:
[tex]k=\dfrac{VL}{Aht}[/tex]
V = 600 ml = 600 cc
L = 8 cm
A = 55 cm²
h = 60 cm
t = 15 mins = 900 sec
[tex]\\[/tex]
[tex]k=\dfrac{(600)(8)}{(55)(60)(900)}[/tex]
[tex]k=1.6162\times10^{-3}[/tex] cm/sec (ANSWER)
2. Seepage velocity, [tex]v_s[/tex]:
[tex]\gamma_d=\dfrac{W_s}{V}[/tex]
[tex]W_s[/tex] = 650 grams
V = AL = (55)(8) = 440 cc
[tex]\\[/tex]
[tex]\gamma_d=\dfrac{650}{440}[/tex]
[tex]\gamma_d=1.4773[/tex] g/cc
[tex]\\[/tex]
[tex]\gamma_d=\dfrac{G_s \gamma_w}{1+e}[/tex]
[tex]e=\dfrac{G_s \gamma_w}{\gamma_d}-1[/tex]
[tex]G_s[/tex] = 2.67
[tex]\gamma_w[/tex] = 1 g/cc
[tex]\gamma_d[/tex] = 1.773 g/cc
[tex]\\[/tex]
[tex]e=\dfrac{2.67(1)}{1.4773}-1[/tex]
[tex]e=0.8074[/tex]
[tex]\\[/tex]
[tex]n=\dfrac{e}{1+e}[/tex]
[tex]n=\dfrac{0.8074}{1+0.8074}[/tex]
[tex]n=0.4467[/tex]
[tex]\\[/tex]
[tex]v=ki[/tex]
[tex]v=k\dfrac{h}{L}[/tex]
[tex]v=(1.6162\times10^{-3})\left(\dfrac{60}{8}\right)[/tex]
[tex]v=0.0121[/tex] cm/sec
[tex]\\[/tex]
[tex]v_s=\dfrac{v}{n}[/tex]
[tex]v_s=\dfrac{0.0121}{0.4467}[/tex]
[tex]v_s=0.0271[/tex] cm/sec (ANSWER)
Solution:
See the attached file which contains the solution.
25. selective permeable membrane
Explanation:
is one that allows certain molecules or ions to pass through it by means of active or passive transport.
26. what is porusity and permeability
porosity is the quality of having pores, or tiny holes
permeability is the quality of soil to transmit water or air
27. The plasma, is similar to a screened window it is permeable to certain kinds of molecules but not to others. Which of the following below fit the description of a cell membrane?A. non-permeableB. permeableC. selectively permeableD. undifferently permeable
the answer is letter c. selectively permeable
28. A person exerts a horizontal force of 190 n in the test apparatus shown in the drawing. find the horizontal forc
Answer:
From the question, we know that The person exerted 190N, force on the flexor is unknown. Since, we don't have access to our diagram, we have to make one or two assumption; (1) that ba= 0.3 m, ac= 0.05.
Therefore, the horizontal force that his flexor muscle exerts on his forearm,F(flexor) = (190N) × (0.3m) / 0.05m.
The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 57 Nm/ 0.05 m.
The horizontal force that his flexor muscle exerts on his forearm,F(flexor) = 1140N.
29. which characterstic of the cell membrane is described as the capacity to regulate what does in and out of cell A high permeability B selective permeability C permeability D none permeability
Answer:
A
Explanation:
high permeabilty, yun lang alam ko
30. How does a conductivity apparatus test whether a solution has ionic or covalent substances?
Explanation:
When the charged particles move that are present in the ionic compounds only in the conductivity apparatus they complete the circuit by the flow of electrons. Hence, a conductivity apparatus test whether a solution has ionic or covalent substances in it as ions complete the flow of electrons to form a circuit etc.
