In coulombs law will a positive charge surrounded by 4 negative charge move? why?
1. In coulombs law will a positive charge surrounded by 4 negative charge move? why?
Answer:
In a wire, negatively charged electrons move, and positively charged atoms don't. Electrical engineers say that, in an electrical circuit, electricity flows one direction: out of the positive terminal of a battery and back into the negative terminal.2. According to Coulomb’s Law, the force of attraction or repulsion, between to electrical charges is?
Answer:
According to Coulomb, the electric force for charges at rest has the following properties:
Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge.
The attraction or repulsion acts along the line between the two charges.
The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. If the charges come 10 times closer, the size of the force increases by a factor of 100.
The size of the force is proportional to the value of each charge. The unit used to measure charge is the coulomb (C). If there were two positive charges, one of 0.1 coulomb and the second of 0.2 coulomb, they would repel each other with a force that depends on the product 0.2 × 0.1. Thus, if each of the charges were reduced by one-half, the repulsion would be reduced to one-quarter of its former value.
The Editors of Encyclopaedia Britannica
This article was most recently revised and updated by Adam Augustyn.
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3. Coulomb’s law predicts that the attraction between two oppositely charged ions:
Answer:
Like charges repel; opposite charges attract. The force is proportional to the magnitude of the charges and inversely proportional to the square of the distance between them.
4. How much charge in coulombs is an 4-uF capacitor charge to 100 v
Answer:
400 μF
Explanation:
Given: C = 4 μF
V = 100 V
Required: Q
Equation: Q = CV
Solution: Q = (4 μF)(100 V)
Answer: Q = 400 μF
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5. Does a charged plastic comb can attract neutral pieces of papers contradicts coulombs law
Answer:
A charged object such as a plastic comb (e.g. charged by rubbing against you hair) can attract a piece of paper which is neutral by inducing electric dipoles in the paper; the 1/r2 dependences of Coulomb's Law => net attraction.
Explanation:
Sana maka tulong po ako
6. a lamp draws a current of 2.0 A. Find the charge in coulombs used by the lamp in 30 ( s ).
Answer:
You can find your Brainly profile link by clicking on your profile picture in the upper right corner. Once you click on your profile picture, the page will reload, and the URL you'll see in your browser should look something like this: https://brainly.com/profile/yourusername-1234567.
7. Activity No. Electricity (Pls. refer on pages 103-106) 1. Explain static electricity. 2. When ca we say that the material is a.positively charged? b. negatively charged? c. neutrally charged? 3. Give practical applications of Coulomb's Law.
Answer:
1. Static electricity is caused by a charge imbalance in an item. These charges may accumulate on an object's surface until they manage to discharge or find a means to be released. Through a circuit is one method of releasing them.
2. a. Positively charged particles include atoms, molecules, and ions that have fewer electrons than protons. On the other hand, a particle is considered to be negatively charged if it has more electrons than protons.
b. Transferring electrons to or taking them away from an item produces an electrical charge. When electrons are introduced to an item, it acquires a negative charge due to the negative charge of electrons.
c. Atoms that are electrically neutral merely have an equal amount of protons and electrons. This balances both types of charges on the items. Ten protons and eleven electrons are present.
3. a. Mixing Substances in Water.
b. Xerox Machine.
c. Charged Rod.
d. Balloon Sticking to Wall.
e. Comb and Bits of Paper.
f. Powder Coating.
g. Electrostatic Air Cleansing.
h. Styrofoam and Aluminum Plate.
Explanation:
8. Directions: Define and explain the following topic in each item.Electric chargeFundamental character of electric chargesConductors and insulatorsCoulomb’s LawElectric field and electric field lines
Answer:
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Explanation:
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9. Draw the net electric force on a +1-C charge placed at the center of a line segment of length 1.0 meter with a +1-C charge and a –1-C charge at its endpoints. Calculate the net force using Coulomb’s law.
Answer:
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10. A sphere of charge 3 coulombs is place in contact with an identical neutral sphere. Each sphere acquired a charge of 1.5 coulombs when separated. What will be the charged of these spheres if two neutral spheres were placed in contact with them?
Answer:
Stuck with me on this the other day you said goodnight to me Friday night when I love yoh so you don't want me smile when you're in the mood and you want me Friday to you so and you then make me cry when you're I don't can't make 368536887 or 4 me anymore and I hope you are doing better 419801772 it was just so much easier for you to get
Explanation:
Way 7 and then go to the game and then we can get you in on a new baby game or another on your way end up and you can make a big difference in the form of electromagnetic and the same amount as you have in your hands that got you in trouble and it will be a little less than you are looking at gumising a great price andito and you can get make a good deal if for some reason you don't want to buy it for free or in order of your business to buy a home and sell the your
11. coulomb's lawif µC yung given unit sa two point charges, need ba siya i-convert sa C?
Answer:
It is necessary to convert it to Coulombs (C) before using it in Coulomb's law. To convert from micro coulombs to Coulombs, you would multiply by 10^-6.
12. Explain how charges, insulators and conductors, Coulomb’s law and electric field are all connected with each other.
Answer:
Conductors are materials that permit electrons to flow freely from particle to particle. ... Conductors allow for charge transfer through the free movement of electrons. In contrast to conductors, insulators are materials that impede the free flow of electrons from atom to atom and molecule to molecule.
Similarities exist between insulators and conductors in terms of structure, hardness and softness, density and doping, which is when some other element or compound is incorporated into an insulator or a conductor to change its electrical behavior. Doping can change a conductor to an insulator and vice versa.
The conductor and insulator are the types of material. One of the major difference between the conductor and insulator is that the conductor allows the energy (i.e., current or heat ) to pass through it, whereas the insulator does not allow the energy to pass through it.
The behavior of an object that has been charged is dependent upon whether the object is made of a conductive or a nonconductive material. Conductors are materials that permit electrons to flow freely from particle to particle. An object made of a conducting material will permit charge to be transferred across the entire surface of the object. If charge is transferred to the object at a given location, that charge is quickly distributed across the entire surface of the object.
Insulators are materials that impede the free flow of electrons from atom to atom and molecule to molecule. If charge is transferred to an insulator at a given location, the excess charge will remain at the initial location of charging. The particles of the insulator do not permit the free flow of electrons; subsequently charge is seldom distributed evenly across the surface of an insulator.
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13. Coulombs Law states that the (8) ____________ between the two electrical charges is (9)_________________ to the product of charges and inversely proportional to the (10) of the distance between them.
Coulombs Law states that the (8) electrical force between the two electrical charges is (9) directly proportional to the product of charges and inversely proportional to the (10) square of the separation of the distance between them.
14. Could Coulomb's Experiment Result in Coulomb's Law?
Answer:
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Explanation:
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Answer:
could colomb is colomb thats colomb
15. How many electrons are there 4.0 coulomb of negative charge?
Answer:
-2.496 x 10^19 electrons
Explanation:
The charge on a single electron is -1.602 x 10^-19 coulomb.
To find the number of electrons in 4.0 coulombs of negative charge, we can divide the total charge by the charge on a single electron:
Number of electrons = (total charge) / (charge on a single electron)
Number of electrons = 4.0 coulombs / (-1.602 x 10^-19 coulombs/electron)
Number of electrons = -2.496 x 10^19 electrons
(Note that the negative sign indicates that the charge is negative, and hence the number of electrons is also negative.)
Therefore, there are approximately 2.496 x 10^19 electrons in 4.0 coulombs of negative charge.
16. PHYS2 Activity 4 Coulomb's Law / Electric Field Direction: Solve the following problems completely. Show complete solution. Use SHORT (letter size) bond paper. 1. A force of 500 Newton exists between two identical point charges separated by a distance of 40cm. Calculate the magnitude of the two point charges. 2. How many electrons represent a charge of -70 micro-Coulomb? 3. The electric force between two point charges with a magnitude of 900 micro- Coulomb and 800 micro-Coulomb is 15 Newton. How far apart are the two charges from each other in millimeter? 4. An -40 micro-Coulomb point charge is placed at the origin. Calculate the magnitude and direction of the electric field created by the point charge at the following location: (a) point P (5m, 0). (b) point Q (3m, 4m).Pahelp mga par...
1.) The force between two point charges is given by Coulomb's law:
F = k * q1 * q2 / r^2
where F is the force, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.
In this problem, we are given F = 500 N, r = 0.4 m, and q1 = q2 = q (since they are identical point charges). So we can write:
500 = (9 x 10^9) * q^2 / (0.4)^2
Solving for q, we get:
q = sqrt(500 * (0.4)^2 / (9 x 10^9)) = 8 x 10^-6 C
So the magnitude of each point charge is 8 micro-Coulombs.
2.) The charge of an electron is -1.6 x 10^-19 C. So to find out how many electrons represent a charge of -70 micro-Coulomb, we can divide:-70 x 10^-6 C / (-1.6 x 10^-19 C/electron) = 4.375 x 10^17 electrons
So a charge of -70 micro-Coulomb is equivalent to the charge of 4.375 x 10^17 electrons.
Using Coulomb's law:
F = k * q1 * q2 / r^2
3.) We are given F = 15 N, q1 = 900 x 10^-6 C, q2 = 800 x 10^-6 C. We need to find r.15 = (9 x 10^9) * (900 x 10^-6) * (800 x 10^-6) / r^2
Solving for r, we get:
r = sqrt((9 x 10^9) * (900 x 10^-6) * (800 x 10^-6) / 15) = 0.4 m = 400 mm
So the two charges are 400 mm apart.
The electric field at a point P due to a point charge Q is given by:
E = k * Q / r^2
4.) where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance between the point charge and the point P.(a) At point P(5m,0), the distance between the point charge and P is:
r = sqrt((5)^2 + (0)^2) = 5 m
So the electric field at point P due to the -40 micro-Coulomb point charge is:
E = (9 x 10^9) * (-40 x 10^-6) / (5)^2 = -2.88 x 10^6 N/C
The negative sign indicates that the electric field is directed towards the point charge.
(b) At point Q(3m,4m), the distance between the point charge and Q is:
r = sqrt((3)^2 + (4)^2) = 5 m
So the electric field at point Q due to the -40 micro-Coulomb point charge is:
E = (9 x 10^9) * (-40 x 10^-6) / (5)^2 = -2.88 x 10^6 N/C
The direction of the electric field at point Q can be found by decomposing it into x and y components:
Ex = E * cos(theta) = -2.88 x 10^6
1. =94.28μC
2. One electron contains a charge of 1.6×10^-19C One coulumb contains 6.25×10^18 electons. The charge of a single electron is (roughly) C.
3. =0.011C
4 Part A
=1.44 × 10⁴ N/C
Part B
E=1.44 × 10⁴ N/C
17. Think! Coulombs Law1. If an electron at a certain distance from a charged particle is attracted with a certain force, how will the force compare at twice this distance2. Is the charged particle in this case positive or negative
Answer:
1. In accord with the inverse-square law, at twice the distance the force will be one fourth as much.
2. Many fundamental, or subatomic, particles of matter have the property of electric charge. For example, electrons have negative charge and protons have positive charge, but neutrons have zero charge.
18. Give practical applications of Coulomb's Law.
Explanation:
Coulomb's Law has a great many applications to modern life, from Xerox machines to laser printers, to powder coating. The ancient peoples living around the Mediterranean Sea knew that if they rubbed a rod of amber on a cat's fur, the rod would attract light objects, such as feathers
19. Charge of a proton and electron in coulombs
Answer:
The charge on 1 proton is 1.6 x 10-19 C. Conversely, the charge of an electron is -1.6 x 10-19 C.
Explanation:
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20. Using Coulomb’s Law, determine the distance in meters between two charges given that the force between the charges is 13,500,000 N and the values of the charges are Q1=-0.5C and Q2=-0.3C. : k = 9,000,000,000 Nm2/C2.
10 meters is the distance between two charges given that the force between the charges is 13,500,000 N and the values of the charges are -0.5 Coulomb and -0.3 Coulomb. (k= 9x[tex]10^{9}[/tex] [tex]\frac{N-m^2}{C^2}[/tex])
The problem asked us to solve using Coulomb's law formula because according to it, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of their distance.
Using Coulombs Law: F= k[tex]\frac{Q1Q2}{r^2}[/tex]
Where:
F is the electric force
Q is the charge in Coulombs
r is the distance of separation
k is the Coulomb constant
Solving for r:
r= [tex]\sqrt{\frac{kQ1Q2}{F} }[/tex] = [tex]\sqrt{\frac{9x10^{9}(-0.3C)(-0.5C) }{13,500,000 N} }[/tex] =10 meters
Thus, the distance between two negative charges, -0.5 C and -0.3 C, is 10 meters.
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21. explain how a charged plastic comb can attract neutral pieces of paper. Does this contradict Coulomb's Law? Why is it difficult to demonstrate this on a humid day?
Answer: yes
Explanation:
The same way that a balloon rubbed on your hair can stick to a neutral wall. When the comb, charged either negatively or positively, is brought near to a neutral piece of paper it repels or attracts the electrons in the paper depending on the comb charge. This results in the atoms or molecules at the microscopic level, and the pieces of paper on the macroscopic level, to become polarized.
This means one side is more positive and the other side is more negative, even though the paper pieces are still overall neutrally charged. The side of the paper facing the comb is always opposite the charge on the comb and therefore feels and attractive force.
This does not contradict Coulomb’s law. There are both attractive and repulsive forces in effect, but by Coulomb’s law the closer charge feels the greater force. Since the charge that is attracted is on the side facing the comb, it is the greater of the two forces.
On a humid day there is a lot of water in the air as individual molecules. Water happens to be a polar molecule, so the positively charged side of the water molecules is attracted by the excess negative charge and tends to pull those electrons away reducing the net charge. This is why we see static electricity problems in the winter when the air is dry, than we see in the summer when the air tends to be more humid.
22. Coulombs law problem solving
Answer:
Coulomb's law states that the electrical force between two charged objects is ... The problem -solving strategy utilized here may seem unnecessary ...
23. 911, I need help. CharDifferentiate the First law of electrostatic charges, Second law of Coulomb's and Faraday's Law
Laws of Electrostatics
First law: Like charges of electricity repel each other, whereas unlike charges attract each other.
Second law:According to this law, the force exerted between two point charges
i) is directly proportional to the product of their strengths.
ii) is inversely proportional to the square of the distance between them. and
iii) is inversely proportional to the of the surrounding medium.
This is known as coulomb's law
hope it help24. The form of coulomb's law is very similar to that for newton`s law of universal gravitation. what are the differences between these two laws
Answer:
The only real difference is that charges can be positive or negative. Both laws look just the same: charges can have opposite signs, and then they attract. If they have the same sign, the force is directed away from each other.
25. Two charges, -4.0 micro coulomb and - 5.0 micro coulomb are separated by a distance of 20cm. What is the electric field midway between the two charges?
itobpo ang answer ko 24cm
26. It is a power that establishes push or pull of two like or unlike charges a. Coulomb’s lawb. Electric forcec. Electric flowd. Electromotive force
Answer:
B. Electric force
Explanation:
Electric force is a force that pushes apart two like charges or that pulls together two unlike charges.
27. How strong is the attractive force between a glass rod with a 0.700 micro-Coulomb charge and a slik cloth with a -0.600 micro-Coulomb charge which are 25 cm apart, using the approximation that they act like point charges?
Answer:0.262 N
Explanation:If charges are distributed, the resultant force between the objects would be the vector sum of each force on each charge due to the resultant electric field at each charge. Things would get complicated
28. Why can’t coulomb’s law be applied to charged bodies that are very near each other?
Answer:
yan po ang answer
Explanation:
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29. Q6. If the reading of the ammeter is 2 A (ampere), how many coulombs of charge passes the cross-section of a conductor in onesecond?1.6 x10lº coulomb b. I coulombc. 1.5 coulombd. 2 coulomb
Answer:
1.
Explanation:
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30. whats is coulomb law
Answer:
Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force
