(-155) + 22/2 - 26 +14? 165-165156-156
1. (-155) + 22/2 - 26 +14? 165-165156-156
Answer:
-156Step-by-step explanation:
i hope it can help!
2. 7. 785 divided by 5 is what number? A. 155 B. 156 C. 157
Answer:
785÷5=157
Answer:C. 157
the answer is letter C. 157 ...3. 1. In the set of height of random students such as 164, 150, 156, 170, 155,168 and 159, the 1st quartile is A. 150 B. 155 C. 156 D. 164
Answer:
The answer is A. 150.
Step-by-step explanation:
Why
4. r[tex]156 \times 156[/tex]
Answer:
the answer is 156 \times 156=24312
5. 1. 2+ 2 = 2. 159 + 156 = 3. 155 + 189 = 4. 166 + 188 = 5. 79 + 29 =
Answer:
1. 4
2. 315
3. 344
4. 354
5. 108
Step-by-step explanation:
6. 9. Find the circumference of a wheel if its diameter is 50 cmA. 154 CM B. 155 CM C. 156 CM D. 157 CM10. Find the circumference of a hula hoop if its radius is 20 in. A. 125.6 in B. 125.8 in C. 126 in D.126 in
Answer:
9. B. 155 CM 10. C. 126 in
Step-by-step explanation:
Pa brainliest
7. Given the following sample statistical data: 120 135 200 179 165 134 Find the following: Range Mean 156 167 177 185 139 140 155 181 192 144 Variance & Standard Deviation (Sample & Population) pa answer po pls
Answer:
apload ka nang guthmath para ma solve na yan
8. 10. The height (in centimeter) of 15 grade 10 students are as follows: 148, 149, 150, 150, 153, 154, 154, 155, 156, 157, 157, 160, 162, 164, and 168. Find the 9th decile. b. 165.2 C. 165.4 d. 165.6 a. 164.8
Answer:
A po 164.8 po ang sagot ko
Step-by-step explanation:
sana po makatulong
9. Directions: Find MEAN, MEDIAN, and MODE of Ungrouped Data given below. Show your complete solution.Given: The height (cm) of randomly selected students in a class are 151, 146, 156, 148, 147, 146, 147, 146, 155, 153
Answer:
ayan po answer sana makatulong btw anong grade to?baka makatulong pako sa inyo hehe
pa heart nalang at pa mark baka naman
10. If the heights of 9 players are 145, 153, 154, 156, 156, 156, 157, 160, and 161, what is the mean of their height??
145 cm - 4.76 ft.
153 cm - 5.02 ft.
154 cm - 5.05 ft.
156 cm - 5.12 ft.
156 cm - 5.12 ft.
156 cm - 5.12 ft
157 cm - 5.15 ft.
160 cm - 5.25 ft.
161 cm - 5.28 ft.
Message:
that's the answer po, centimeter to feet height converter, marking me as the brainliest will be a big help, thank you I hope I helped!
11. 3. Write 15 x 15 x 15 x 15 x 15 in exponential notation or exponential forma. 515b. 155c. 156d. 615
Answer:
B
Step-by-step explanation:
B po ang tamang sagot dyan
Answer:
B.15 to the 5th power
Step-by-step explanation:
12. 2. Myrna finds a hat that cost P116 and a comb that costs P42.How much does she need to pay? *a.155b.156c.157d.158
Answer:
The answer is D. 158
Step-by-step explanation:
₱116
+₱ 42
₱158
13. the height (in centimeters) of 15 grade 10 student are as fallows 148 149 150 150 153 154 155 156 157 160 162 164 and 168 find the 9th decile
Answer:
165.6
Step-by-step explanation:
Data are already in ascending orders.
There are 15 numbers in total
(n+1) P = (15+1) x 9/10 = 14.4
x(14) = 164 x(15) = 168
x(14)+ 0.4 { x(15) - x(14) }
= 164 + 0.4x4
= 164 + 1.6
= 165.6
{CALCULATION OF DECILE}
14. Find the range of each set of data given below: 1.3, 8, 16, 12, 4, 5, 7, 15 2. 25, 32, 9, 18, 12, 30, 28, 22 3. 8.5, 6.2, 12, 4.2, 14, 9.1, 15.3 4. The heights in centimeters of the students in a class. Male: 150, 151, 157, 157, 154, 155, 156, 158, 160, 161, 166 Females: 144, 145, 146, 147, 149, 150, 152, 153, 155, 156, 157
Answer:
See the analysis
Explanation:
#CarryOnLearning✨15. Which of the following statements is NOT true about the two data sets below? Set A: 156, 175, 122, 141, 178, 111 147.17 148.5 Set B: 189, 210, 167, 100, 125, 143 155.67 155
Answer:
110, 121, 122, 122, 123, 132, 132, 132, 133, 134, 134, 136, 138, 140, 141, 142, 143, 143, 143, 145, 145, 145, 145, 146, 150, 154, 155, 156, 159, 159, 162, 163, 165, 167, 167, 168, 169, 170, 172, 174, 175, 177, 178, 178, 187, 187, 188, 189, 191, 194.That is The Correct Order
Step-by-step explanation:
pa brainliest pls :D wala naman mawala sayo :D16. what is the standard division of 160 cm 166 cm 155 cm 158 cm 162 cm 170 cm 156 cm 153 cm
Answer:
5.78 cm
Step-by-step explanation:Formula:
[tex]\sf \sigma = \sqrt{\frac{\sum(x_i - \mu)^2}{n-1} }[/tex]
[tex]\textsf{where} \begin{cases} \sf n = number \: of \: terms\\\sf \mu = mean\\\sf x_i = individual \: values \: of \: the \: terms \: on \: the \: sample\end{cases}[/tex]
Solution:
[tex]\sf \textsf{Given: } \{160,166,155,158,162,170,156,153\}[/tex]
[tex]\sf In \: this \: case, \; x_i = \{160,166,155,158,162,170,156,153\}[/tex]
[tex]\sf By \: counting \: the \: number \: of \: terms, \: n = 8[/tex]
[tex]\textsf{Solving for the mean }\sf \mu,[/tex]
[tex]\sf \mu = \frac{160+166+155+158+162+170+156+153}{8} = 160[/tex]
[tex]\therefore \sf (x_i - \mu)^2 = \begin{cases} \sf (160 - 160)^2 = 0\\ \sf (166 - 160)^2 = 36 \\ \sf (155 - 160)^2 = 25 \\ \sf (158 - 160)^2 = 4 \\ \sf (162 - 160)^2 = 4 \\ \sf (170 - 160)^2 = 100 \\ \sf (156 - 160)^2 = 16 \\ \sf (153 - 160)^2 = 49\end{cases}[/tex]
[tex]\sf It \: follows \: that[/tex]
[tex]\sf \sum(x_i-\mu)^2 = 0 + 36 + 25 + 4 + 4 + 100 + 16 + 49\\\text{} \quad \quad \quad \quad \ \ \ = 234[/tex]
[tex]\sf Substituting \: to \: the \: formula,[/tex]
[tex]\sf \sigma = \sqrt{\frac{\sum(x_i - \mu)^2}{n-1} } = \sqrt{\frac{234}{8-1} }[/tex]
[tex]\sf \sigma = \sqrt{33.4285714286} \approx 5.78 \: cm[/tex]
#CarryOnLearning
17. a book is open to pages where the sum of the two pages number facing the reader is 313 which is the bigger of the two page numbers?A. 155 B. 156C. 157D. 158
Answer:
C
Step-by-step explanation:
minus lng ginawa ko jan
Answer:
C
Step-by-step explanation:
tama po ung unang sumagot
18. Number of Students 25 20 15 10 S 0 Students Height after the Quarantine (in cm) Under 151 151 155 156-160 161-165 Students' Height (in cm) 166-170 Over 170 1. Give the number of students in each height interval. Under 151 cm 151 - 155 cm 156-160 cm 161 165 cm 166-170 cm Over 170 cm 2. How many students are in the 166-170 cm interval? 3. How many students are between 156 cm and 170 cm in height? 4. How many students are above 160 cm in height? 5. How many students are below 156 cm in height? 6. How many students are there in all? Number of Students 25 20 15 10 S 0 Students Height after the Quarantine ( in cm ) Under 151 151 155 156-160 161-165 Students ' Height ( in cm ) 166-170 Over 170 1. Give the number of students in each height interval . Under 151 cm 151 - 155 cm 156-160 cm 161 165 cm 166-170 cm Over 170 cm 2. How many students are in the 166-170 cm interval ? 3. How many students are between 156 cm and 170 cm in height ? 4. How many students are above 160 cm in height ? 5. How many students are below 156 cm in height ? 6. How many students are there in all ?
1. Give the number of students in each height interval.
Under 151 cm - 1
151 - 155 cm - 14
156 - 160 - 20
161 - 165 - 18
166 - 170 - 12
Over 170 - 0
2. How many students are in the 166-170 cm interval?
12 students
3. How many students are between 156 cm and 170 cm in height?
20 students
4. How many students are above 160 cm in height?
30 students
5. How many students are below 156 cm in height?
15 students
6. How many students are there in all?
65 students
19. 5.What is wind speed of category 2?A.111-130 mph or 181-210 kphB.96-110 mph or 151-180 kphC.131-155 mph or 211-250 kphD.156 mph+ or 250 kph+What is the answer?
Answer:A
Explanation:because the wind of categoty 1 is 96-110mph
20. What's 12 x 12? A. 155 B. 144 C. 156 D. 123 Choose wisely.
Answer:
the answer is letter B
hope it helps you
thanks for the points
21. -156 subtracted from -156
Answer:0
Step-by-step explanation:
22. I.Total Scores Obtained in Performance Tasks in Mathematics 10 of 20 Grade10 Students:143, 119, 146, 178, 170, 167, 139, 165, 155, 173,173, 141, 161, 176, 173, 173, 156, 181, 175, 111Find:1. PS
Answer:
huh?
Explanation:
23. 5 > 24. What is 53 + 25? C. 156 d. 157 a. 154 b. 155
Answer:
What is 53+25?ANSWER!53+25=78
24. What is the approximate capacity of a small can of sardines? a. 155 cgb. 155 gc. 155 hgd. 155 kg
Answer:
B. 155 g
Step-by-step explanation:
Answer: B
Step-by-step explanation:
25. The following are the heights in centimeter of 15 Mathematics Teachers in St.Martin's Academy: 162 160 152 164 154 163 163 155 161 165 156 165 166 160 151 Compute for the mean, median and mode
Answer:
Step-by-step explanation:
To compute for the mean, median, and mode of the given heights:1. Mean:
Add all the heights and divide the sum by the total number of heights.
Mean = (162 + 160 + 152 + 164 + 154 + 163 + 163 + 155 + 161 + 165 + 156 + 165 + 166 + 160 + 151) / 15
Mean = 159.67 cm
2. Median:
Arrange the heights in ascending or descending order, and find the middle value. If there are two middle values, compute their average.
Arranging the heights in ascending order, we get:
151 152 154 155 156 160 160 161 162 163 163 164 165 165 166
Since there are 15 heights, the median is the value in the 8th position (counting from the smallest):
Median = 161 cm
3. Mode:
The mode is the value that appears most frequently in the data set.
In this case, we have two modes: 160 cm and 163 cm, as both heights appear twice in the data set.
Therefore, the mean height of the 15 Mathematics Teachers in St. Martin's Academy is 159.67 cm, the median height is 161 cm, and the mode is 160 cm and 163 cm.
26. The Following are the heights to the nearest centimeter of 15 English teachers in St. Joseph's Academy. 162 160 164 154 163 155 165 156 166 160 Compute the following: a. population mean b. population variance c. population standard deviation
Answer:
To compute the population mean, we add up all the heights and divide by the number of teachers:
a. Population mean = (162 + 160 + 164 + 154 + 163 + 155 + 165 + 156 + 166 + 160) / 10 = 1608 / 10 = 160.8 cm
To compute the population variance, we first need to calculate the deviation of each height from the mean:
Deviation of each height from the mean:
(162 - 160.8) = 1.2
(160 - 160.8) = -0.8
(164 - 160.8) = 3.2
(154 - 160.8) = -6.8
(163 - 160.8) = 2.2
(155 - 160.8) = -5.8
(165 - 160.8) = 4.2
(156 - 160.8) = -4.8
(166 - 160.8) = 5.2
(160 - 160.8) = -0.8
To compute the population variance, we need to square each deviation, add up the squares, and divide by the number of teachers:
b. Population variance = [(1.2^2) + (-0.8^2) + (3.2^2) + (-6.8^2) + (2.2^2) + (-5.8^2) + (4.2^2) + (-4.8^2) + (5.2^2) + (-0.8^2)] / 10 = 60.16
To compute the population standard deviation, we take the square root of the variance:
c. Population standard deviation = sqrt(60.16) = 7.76 cm
27. For items 16-20. Refer to Table 1. 16. What is the lower limit of the 3rd class interval? a. 156 b. 151 c. 146 d. 141 17. What is the class size of each class interval? a. 4 b. 5 c. 6 d. 7 18. Which class interval has the highest frequency? a. 141-145 b. 151-155 c. 156-160 d. 161-165 19. What is the total frequency? a. 50 b. 55 c. 60 d. 65 20. What is the class mark of the 2nd class interval? a. 143 b. 148 c. 158 d. 163 Table 1 Height (cm) Frequency Distribution Height in cm Frequency 161-165 6156-160 5151-155 18146-150 14141-145 7
Answer:
a
c
b
a
Step-by-step explanation:
yan po yung sagot ko correct me if i wrong
28. EXERCISE:FIND Q1 Q2. D4 D7 D92. 100 111 123 112 132141 145 150 155 156160 101 102 102 103
Answer:
FRACTILES GROUP 4
2. Fractiles are measures of location or position which include not only central location but also any position based on the number of equal divisions in a given distribution. If we divide the distribution into four equal divisions, then we have quartiles denoted by Q1, Q2, Q3, and Q4. The most commonly used fractiles are the quartiles, deciles, and percentiles.
3. Fractiles for Ungrouped Data QUARTILES divide a distribution into four equal parts. For example, Q1, or the first quartile, locates the point which is greater than 25% of the items in distribution. Q3 is the 3rd quartile Q3 = 3N th item 4 This means that 75% of the observations lie below this value.
4. Q2 is the 2nd quartile Q2 = 2N th item or the median 4 Q1 is the 1st quartile Q1 = N th item 4
5. DECILES are values that divide a distribution into 10 equal parts. D1 is the 1st decile D1 = N th item 10 D3 is the 3rd decile D3 = 3N th item 10 D5 is the 5th decile D5 = 5N th item or the median . 10
6. PERCENTILES are values that divide the distribution into 100 equal parts. P10 or the tenth percentile means the 10th item in the distribution which is 10% higher than the rest of the items. P1 is the 1st percentile P1 = Nth item 100 P25 is the 25th percentile P25 = 25Nth item or Q1 100
7. P50 is the 50th percentile P50 = 50Nth item or the median 100 P67 is the 67th percentile P67 = 67Nth item 100
8. Example 1: Calculate Q1, Q2, Q3, D1, D4, D5, D7, P10, P25, P50 and P70 for the following IQ scores: 87 90 95 96 97 98 98 99 100 100 100 100 100 101 101 102 102 102 103 104 105 107 110 Q1 = N th = 23 th = 5.75th item, which is 98. 4 4
9. Note: for odd number of observations, when the item number is fractional, take the next higher item. Since the 5th item 97, the 5.75th item is the next value, which is 98. This means that the score of 98 is higher than 25% of the items in the distribution. If the number of cases is even, take the point midway between the two items located at the middle of the distribution.
10. Q2 = 2N th = 2(23) th = 23 th = 11.5th item, 4 4 2 which is 100. This means that the score of 100 is higher than 50% of the items in distribution. Q3 = 3N th = 3(23) th = 69 th = 17.25 th item, 4 4 4 which is 102. D1 = N th = 23 th = 2.3 th item, which is 95. 10 10
11. D4 = 4N th= 4(23)th= 92 th=9.2th item, which is 100. 10 10 10 D5= 5N th= 5(23)th= 115 th= 11.5th item, which is 100. 10 10 10 D7= 7N th=7(23)th= 161 th=16.1th item, which is 102. 10 10 10 P10= 10N th=10(23)th= 23 th=2.3th item, which is 95. 100 100 10 P25= 25N th=25(23)th= 23 th=5.7th item, which is 98. 100 100 4
12. P50= 50Nth=50(23)th= 23th=11.5th item, which is 100. 100 100 2 P70= 70Nth=70(23)th= 1,610th=16.1th item, 100 100 100 which is 102. NOTE: that median is equal to Q2, D5, and P50
13. Grouped data • Estimate the cumulative frequencies on the table • Find N/4 or one-fourth of the number of the cases in the distribution. • Determine the class limit in which N/4 case falls • Compute Q1 by using the formula; Q1 = L+C (N/4-ΣCf<) fc
14. Where ; Q1 = is the first quartile L = lower real limit of the first quartile class N = total number of cases ΣCf< = sum of the cumulative frequencies “ lesser than” up to but below the first quartile class C = class interval fc =
Step-by-step explanation:
mahaba po yung iba ito lang po kaya ko
29. A. The table below shows the heights in centimeters of 50 students in Grade 10 Math.155 175 167 165 175176 167 154 153 170151156 163 165 170165 159 178 177 173160153 176 178172173 161 155 183 175166150182176158167172173 158155173151159171174175165160170154
Answer:
Height (in cm) Frequency
150−155 12
155−160 9
160−165 14
165−170 10
170−175 5
Total 50
(i) The above table is the grouped frequency distribution.
(ii) Students with 160−165cm heights are maximum i.e. 14 students.
Step-by-step explanation:
Paki brainlist po please
30. 8. When 785 is divided by 5, what is the number? A. 155 B. 156 C. 157 D. 158
Answer:
C answerStep-by-step explanation:
HOPE IT HELPS